If perimeter of square field is (4x - 12), then find the side of the field.

x - 6

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2x - 6

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x - 3

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2x + 6

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Solution

The correct option is C x - 3
Perimeter of a square is four times the side of the field.
Given, perimeter = 4x-12
So, side of the field $= \frac{(4 x - 12)}{4}$
= $\frac{4 x}{4} - \frac{12}{4} = x - 3$

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