Question

If pH of solution of NaOH is 12.0, then pH of $H_{2}S{O}_4$ solution of same molarity will be:

• A. 2
• B. 12
• C. 1.7
• D. 10

Answer 1

Answer: (C)

1.7

For NaOH solution, $pH=12.0$.

$pOH=14.0-pH=14.0-12.0=2.0$

$[H{]}^{+}={10}^{-pH}={10}^{-2.0}$

This is the molarity of NaOH solution.

It is also equal to the molarity of $H_{2}S{O}_4$ solution.

For, $H_{2}S{O}_4$ solution,

$[H{]}^{+}=2\times {10}^{-2.0}$

$pH=2-log2=1.7$.