If - - cos- -sin- 1- sin- cos- 1- cos - -sin - 1 - the

The correct options are A ϕ (300, 200) = ϕ (400, 200) nbsp; C ϕ (100, 200) = ϕ (200, 200) nbsp;ϕ (α, β) =cosα amp; sinα amp; 1 sinα amp; cosα am ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Evaluation of a Determinant

If ϕα, β=|[ ...

Question

If $ϕ (α, β) = ∣ ∣ ∣ ∣ \begin{matrix} cos α & - sin α & 1 sin α & cos α & 1 cos (α + β) & - sin (α + β) & 1 \end{matrix} ∣ ∣ ∣ ∣,$ then

ϕ (300, 200) = ϕ (400, 200)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

ϕ (200, 400) = ϕ (200, 600)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

ϕ (100, 200) = ϕ (200, 200)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

ϕ (α, β) =

∣ ∣ ∣ ∣ \begin{matrix} cos α & - sin α & 1 sin α & cos α & 1 cos (α + β) & - sin (α + β) & 1 \end{matrix} ∣ ∣ ∣ ∣

∣ ∣ ∣ ∣ \begin{matrix} cos α & - sin α & 1 sin α & cos α & 1 cos (α + β) & - sin (α + β) & 1 \end{matrix} ∣ ∣ ∣ ∣

cos (α - β) = sin (α + β)

\frac{1}{1 - sin α} =

\frac{2 sin α}{1 + cos α + sin α} = x

\frac{1 - cos α + sin α}{1 + sin α}

\sin α + \sin β = a and \cos α + \cos β = b

\sin (α + β) = \frac{2 a b}{a^{2} + b^{2}}

\cos (α - β) = \frac{a^{2} + b^{2} - 2}{2}

Join BYJU'S Learning Program