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Question

If π < 2θ < 3π2 then 2+2+2cos4θ is equal to


A

-2sinθ

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B

-2sinθ

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C

2cosθ

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D

2sinθ

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Solution

The correct option is D

2sinθ


2+2(1+cos4θ) = 2+2|cos2θ|

= 2(1cos2θ) = 2|sinθ| = 2sinθ as π2 < θ < 3π4


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