Question

If $\pi$ is the Peltier coefficient, heat evolved at a junction when a current of 10 mA passes for 10 seconds, in joules is

• A. $\frac{\pi }{10}$
• B. 10 $\pi$
• C. 100 $\pi$
• D. $\frac{1}{10}$

Answer 1

Answer: (A)

$\frac{\pi }{10}$

we know that $\pi =\frac{\Delta H}{\Delta Q}$
$Q=i\times t$
so $H=\pi i\times {10}^{-3}t$

Put $i=10mA=10\times {10}^{(}-3)A$

$t=10s$

$H=\frac{\pi }{10}$ joule

NOTE: here (Q) is in watt and (H) is in joule