Question

If Plank's constant is larger than its present value. The de-Broglie wavelength associated with material particles would have been

• A. unchanged
• B. larger
• C. smaller
• D. larger for some particles and smaller for others

Answer 1

The correct option is B larger

de-Broglie wavelength associated with the particle is given by $\lambda =\frac{h}{P}$
where $h$ is Planck's constant and $P$ is the momentum of particle.
$⟹\lambda \propto h$
Thus de-Broglie wavelength associated with the particle will be larger if the value of Planck's constant is larger than its present value.