Question

If plants with genotypes RrYy and rryy are crossed with each other, then what percentage of progenies produced in F₁ generation would be heterozygous for both the characters?

यदि जीनप्ररूप (जीनोटाइप) RrYy तथा rryy वाले पादपों का एक-दूसरे के साथ संकरण करवाया जाए तो F₁ पीढ़ी में उत्पन्न होने वाले कितने प्रतिशत संतति दोनों अभिलक्षणों के लिए विषमयुग्मजी होंगे?

• A. 50%
• B. 75%
• C. 25%
• D. 100%

Answer 1

Answer: (C)

Dihybrid cross:

1. The genotypes of the parents are given as RrYy and rryy.
   
2. The possible gametes from the first parent can be RY, Ry, rY, ry.
   
3. ​The possible gametes from the second parent is only ry.
   
4. Now the $F_1$ generation from the given gametes can be shown as a part of a Punnett square.
   

Gametes	RY	Ry	rY	ry
ry	RrYy	Rryy	rrYy	rryy

1. Out of all possible offspring, there is only one with the heterozygous genotype for both the characters.
   

Final Answer: Therefore, the possibility of getting a progeny that is heterozygous for both characters is $\frac{1}{4}=0.25$ .