If PN be the ordinate of a point P on the hyperbola x2(97)2−y2(79)2=1 and the tangent at P meets the transverse axis in T, O is the origin; if ON×OT=k then √k+114 is equal to
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Solution
From properties of hyperbola IF PN be the ordinate of a point P on the hyperbola and tangent at P meets the transverse axis in T, then ON.OT=a2 , o being the origing ∴k=ON×OT=972=9409