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Question

If point P(3,8) lies on the line segment joining A(2,10) and B(6,2), then:

[1 mark]

A
AP=AB4
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B
AP=BP
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C
AB=4BP
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D
AP=AB3
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Solution

The correct option is A AP=AB4

Using the section formula,
P(3,8)=(mx2+nx1m+n,my2+ny1m+n)(3,8)=(m(6)+n(2)m+n,m(2)+n(10)m+n)3=6m+2nm+n
3(m+n)=6m+2n
n=3m
m:n=1:3
Option A : Ap=AB4
AP=m=1
AB=m+n=1+AB4
AP=AB4

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