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Question

If point P(h,k) on the curve y=x+lnx is at the shortest distance from straight line y=2x+3. Then the value (h+k) is

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Solution

For shortest distance, slope of tangent on the curve will be equal to slope of line.
Now, first curve :y=x+lnx
Differentiating both sides w.r.t. x,
y=1+1x
At point P(h,k),y=1+1h
(dydx)c1=(dydx)c2
1+1h=2
h=1, and(h,k) satisfies y=x+lnx
k=1
h+k=2

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