If points (a, 0), (0, b) and (x, y) are collinear, then will hold true.
A
xa+yb=1
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B
xa−yb=1
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C
ya+xb=1
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D
ya−xb=1
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Solution
The correct option is Axa+yb=1 Let A(a, 0), B(0, b) and P(x, y) be the collinear points. ⇒SlopeofAB=SlopeofBP⇒b−00−(−a)=y−bx−0⇒−ba=y−bx⇒−xb=ay−ab⇒xb+ay=ab⇒xa+yb=1