If points $A$ $(2, 0)$ and $B$ $(8, - 4)$ are the endpoints of diameter $A B$ of circle $O$ , then the area of circle O is?

10 π

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13 π

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24 π

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26 π

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Solution

The correct option is C $13 π$
The length of the diameter is computed from the distance formula:
$A B = \sqrt{(2 - 8)^{2} + (0 - (- 4))^{2}} = \sqrt{52}$
The area of the circle is then:
$\frac{π A B^{2}}{4} = \frac{52 π}{4} = 13 π$
So option B is the right answer.

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If points A (2,0) and B (8,−4) are the endpoints of diameter AB of circle O, then the area of circle O is?

The correct option is C 13πThe length of the diameter is computed from the distance formula:AB=√(2−8)2+(0−(−4))2=√52The area of the circle is then:πAB24=52π4=13πSo option B is the right answer.

If points $A$ $(2, 0)$ and $B$ $(8, - 4)$ are the endpoints of diameter $A B$ of circle $O$ , then the area of circle O is?

The correct option is C $13 π$
The length of the diameter is computed from the distance formula:
$A B = \sqrt{(2 - 8)^{2} + (0 - (- 4))^{2}} = \sqrt{52}$
The area of the circle is then:
$\frac{π A B^{2}}{4} = \frac{52 π}{4} = 13 π$
So option B is the right answer.