If points ^i+^j,^i−^j and p^i+q^j+r^k are collinear, then
A
p=1
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B
r=0
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C
q∈R
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D
q≠1
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Solution
The correct options are Ar=0 Bp=1 Dq≠1 Points A(^i+^j),B(^i−^j) and C(p^i+q^j+r^k) are collinear Now →AB=−2^j and →BC=(p−1)^i+(q−1)^j+rk Vectors →AB and →BC must be collinear ⇒p=1,r=0 and q≠1