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Question

If polynomial p(x) is divided by x2+3x+5, the quotient polynomial and the remainder polynomials are 2x2+x+1 and x=3 respectively. Find P(x).

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Solution


We know that the division algorithm states that:
Dividend=Divisor×Quotient+Remainder

It is given that the divisor is x2+3x+5, the quotient is 2x2+x+2 and the remainder is 3. And let the dividend be p(x). Therefore, using division algorithm we have:

p(x)=[(x2+3x+5)(2x2+x+1)]+3=[x2(2x2+x+1)+3x(2x2+x+1)+5(2x2+x+1)]+3=2x4+x3+x2+6x3+3x2+3x+10x2+5x+5+3=2x4+7x3+14x2+8x+8

Hence, the dividend p(x) is 2x4+7x3+14x2+8x+8.

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