If ∠POR and ∠QOR are forming a linear pair, then find the value of x.

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Solution

$< P O R$ and $< R O Q$ is making a linear pair.

Therefore, $< P O R + < R O Q = 180^{o}$ .

=> $2 x + 3 x$ = $180^{o}$

=> $5 x$ = $180^{o}$

=> $x$ = ${(\frac{180}{5})}^{o}$

=> $x = 36^{o}$ .

Thus, the two angles are $2 x = 72^{o}$ and $3 x = 108^{o}$ .

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