Question

If possible, maximize $z=x+4y$, subject to $3x+6y\le 6,4x+8y\ge 16$ and $x\ge 0,y\ge 0$.

Answer 1

Given: $z=x+4y$, subject to $3x+6y\le 6,4x+8y\ge 16$ and $x\ge 0,y\ge 0$

After plotting $3x+6y\le 6$ and $4x+8y\ge 16$ on graph paper we get the as shown.

As we can see in the image, there is no intersection area between the two equation, so it is $not$ $possible$ to maximize $z$.