If potential at point A, B and C are 48 V, 24 V and 0 V respectively, the current through resistance R will be

3 A

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4 A

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6 A

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Solution

The correct option is B 4 A
Given,
$V_{A} = 48 V$
$V_{B} = 24 V$
$V_{C} = 0 V$

Apllying kirchhoff's current law at the junction, we get relation between $I_{1}$ , $I_{2}$ and $I_{3}$ as,
$I_{1} = I_{2} + I_{3}$ ---------(1)
Also,
From ohm's law, we have
$I = \frac{V}{R}$
So,
$I_{1} = \frac{48 - 24}{4} = 6 A$
$I_{3} = \frac{24 - 0}{12} = 2 A$
Putting the values of $I_{1}$ , $I_{2}$ and $I_{3}$ in equation (1), we get
$6 = I_{2} + 2$
or,
$I_{2} = 4 A$
Thus, current through resistance R is 4 A.

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