If potential energy density is twice the average rate of transmission of potential energy. The speed of transverse wave is
A
0.5m/s
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B
2m/s
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C
5m/s
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D
1m/s
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Solution
The correct option is A0.5m/s Potential energy density is the potential energy per unit length of string, <dUdx>=14μω2A2
Avg. rate of transmission of potential energy is, <dUdt>=14μvω2A2
Given: <dUdx>=2<dUdt> ⇒14μω2A2=2×14μvω2A2 ⇒v=12=0.5m/s