Question

If power factor is $\frac{1}{2}$ in a series RL circuit R = 100$\Omega$. AC mains is used then L is

• A.
• B. πHenry
• C.
• D. None of these

Answer 1

The correct option is A

$cos\varphi =\frac{1}{2}\Rightarrow \varphi ={60}^{\circ },tan{60}^{\circ }=\frac{\omega L}{R}\Rightarrow L=\frac{\sqrt{3}}{\pi }$H