The correct option is B 48∘, 84∘
Consider the △ORS.
Note that OR = OS = radius of the circle. Since the angles opposite to equal sides are equal, we have ∠ORS=∠OSR=48∘.
But, using angle sum property
∠ORS+∠RSO+∠SOR=180∘.
i.e., 48∘+48∘+∠SOR=180∘
⟹∠SOR=180∘−96∘=84∘
Now, since equal chords subtend equal angles at the centre and since PQ=RS,
∠SOR=∠POQ=84∘.
It can be noted that △OPQ is also isosceles.
⟹∠OPQ=∠OQP
Thus, using angle sum property in △OPQ,
∠OPQ=180∘−84∘2=48∘.