If pqr - 1- then 1-1-p-q-1-1-1-q-r-1-1-1-r-p-1 is equal to

The correct option is A 1 1/1+p+q^ 1+1/1+q+r^ 1+1/1+r+p^ 1 = #160; 1/1+p+q^ 1+q^ 1/q^ 1+1+q^ 1r^ 1+p/p+pr+1 = #160; 1/1+p+q^ 1+q^ 1/1+q^ ...

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Special Integrals - 1

If pqr = 1,...

Question

If $p q r = 1$ , then $(\frac{1}{1 + p + q^{- 1}} + \frac{1}{1 + q + r^{- 1}} + \frac{1}{1 + r + p^{- 1}})$ is equal to

1

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p q

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q r

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\frac{1}{p q}

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Solution

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Similar questions

If $p > q > 0 a n d p r < - 1 < q r$ , then find the value of

{tan}^{- 1} \frac{p - q}{1 + p q} + {tan}^{- 1} \frac{q - r}{1 + q r} + {tan}^{- 1} \frac{r - p}{1 + r p} .

$I f P (Q - r) x^{2} + Q (r - P) x + r (P - Q) = 0 h a s e q u a l r o o t s t h e n \frac{2}{Q} = (w h e r e P, Q, r ϵ R)$

p^{x - 1} = q r, q^{y - 1} = r p, r^{z} - 1 = p q,

\frac{1}{x} + \frac{1}{y} + \frac{1}{z}

$p q^{2} + q (p - 1) - 1 = ? (a) (p q + 1) (q - 1) (b) p (q + 1) (p - 1) (c) q (p - 1) (q + 1) (d) (p q - 1) (q + 1)$

[\frac{x^{q}}{x^{r}}]^{\frac{1}{q r}} \times [\frac{x^{r}}{x^{p}}]^{\frac{1}{r p}} \times [\frac{x^{p}}{x^{q}}]^{\frac{1}{p q}} = 1

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