Question

If PQRS is a square then write the measure of $\angle SRP$.

Answer 1

In square PQRS,

Join PR,

$\because$ Diagonals of a square bisect are opposite angles

$\therefore \angle SRP=\frac{1}{2}\times \angle SRQ$

$=\frac{1}{2}\times {90}^{\circ }={45}^{\circ }$