Question

If Pranam has $x$ apples and Prathik has four more than thrice the number of apples Pranam has, then the total number of apples with Pranam and Prathik is algebraically written as

• A. $\left(3x\right)+(4+3x)$
• B. $x+4$
• C. $\left(x\right)+(4+3x)$
• D. $x+3x)$

Answer 1

The correct option is C

$\left(x\right)+(4+3x)$

Given Pranam has $x$ apples.

Then 'thrice the number of apples Pranam has' is algebraically written as $3x$ and hence 'four more than thrice the number of apples Pranam has' is algebraically written as $4+3x$.

Thus the total number of apples with Pranam and Prathik is given by the sum of the number of apples with Prathik and the number of apples with Pranam.

So, the total number of apples with Pranam and Prathik is algebraically written as '$\left(x\right)+(4+3x)$'.