If pressure becomes double at the same absolute temperature on 2 L of $C O_{2}$ , then what will be the final volume of $C O_{2}$ ?

2 L

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4 L

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25 L

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1 L

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Solution

The correct option is D 1 L
When the temperature of a gas is kept constant, the volume of a fixed mass of gas is inversely proportional to its pressure i.e. PV = Constant

Let, initial pressure $(P_{1})$ = 1 atm.
Then final pressure $(P_{2})$ = 2 atm
Initial volume $(V_{1})$ = 2 L
Final volume $(V_{2})$ = ?

$\frac{P_{1}}{P_{2}}$ = $\frac{1}{2}$

Since, PV = Constant, $P_{1} \times V_{1} = P_{2} \times V_{2}$

$\frac{V_{1}}{V_{2}}$ = $\frac{P_{1}}{P_{2}}$ = $\frac{2}{1}$

$\frac{2 L}{V_{2}}$ = $\frac{1}{2}$ ; $V_{2}$ = 1L

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