If pressure becomes double at the same absolute temperature on 2 L of $C O_{2}$ , then the final volume of $C O_{2}$ will be?

2 L

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4 L

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25 L

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1 L

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Solution

The correct option is D
1 L

$\frac{P_{1}}{P_{2}}$ = $\frac{1}{2}$

$\frac{V_{1}}{V_{2}}$ = $\frac{P_{1}}{P_{2}}$ = $\frac{2}{1}$

$\frac{2 L}{V_{2}}$ = $\frac{1}{2}$ ; $V_{2}$ = 1L

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