If pressure becomes double at the same absolute temperature on 2 L of ${CO}_{2}$ , then what will be the final volume of ${CO}_{2}$ ?

Open in App

Solution

When the temperature of a gas is kept constant, the volume of a fixed mass of gas is inversely proportional to its pressure i.e. PV = Constant

Let, initial pressure $(P_{1})$ = 1 atm
Then final pressure $(P_{2})$ = 2 atm
Initial volume $(V_{1})$ = 2 L
Final volume $(V_{2})$ = ?

$\frac{P_{1}}{P_{2}}$ = $\frac{1}{2}$

Since, PV = Constant, $P_{1} \times V_{1} = P_{2} \times V_{2}$

$\frac{V_{1}}{V_{2}}$ = $\frac{P_{2}}{P_{1}}$ = $\frac{2}{1}$

$\frac{2 L}{V_{2}}$ = $\frac{2}{1}$ ;
$V_{2}$ = 1 L

Suggest Corrections

Similar questions

C O_{2}

C O_{2}

If pressure becomes double at the same absolute temperature on 2 L of $C O_{2}$ , then the final volume of $C O_{2}$ will be?

If pressure becomes double at the same absolute temperature on 2 L of $C O_{2}$ , then what will be the final volume of $C O_{2}$ ?

2 L

C O_{2}

C O_{2}

If pressure becomes double at the same absolute temperature on 2 L of $C O_{2}$ , then the final volume of $C O_{2}$ will be?

Join BYJU'S Learning Program