Question

If pressure of ${CO}_2$ (real gas) in a container is given by $P=\frac{RT}{2V-b}-\frac{a}{4b^2}$, then mass of the gas in container is:

• A. $11g$
• B. $22g$
• C. $33g$
• D. $44g$

Answer 1

Answer: (B)

$22g$

According to Van Der waal's equation for $n$ mole of real gas

$(P+\frac{n^{2}a}{V^2})(V-nb)=nRT⟹P=\frac{nRT}{V-nb}-\frac{n^{2}a}{V^2}$

Given that Pressure of $C{O}_2$ gas in a contaner is given by:

$P=\frac{RT}{2V-b}-\frac{a}{4b^2}$

Compairing it with the standard Van der waal's equation we get :

$n=\frac{1}{2}$

Therefore, Number of moles in a container , $n=\frac{1}{2}$

Molar mass of $C{O}_2=44gm$

Mass of gas in the container, $m=\frac{1}{2}\times 44=22gm$