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Question

If pressure P, velocity V and time T are taken as fundamental physical quantities, the dimensional formula of force is

A
[P1V2T2]
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B
[PV2T2]
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C
[P1VT2]
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D
[PVT2]
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Solution

The correct option is B [PV2T2]
According to the question force,
FPαVβTγ
by substituting the dimensions,
[MLT2]=[ML1T2]α[LT1]β[T]γ
Comparing the power on both sides,
α=1
α+β=1
2αβ+γ=2
by solving above equation, we get
α=1, β=2 and γ=2
so,
FPV2T2
dimensional formula of force=[PV2T2]

Final answer: (a)

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