Question

If probability of "not $E$"$=0.95$, then find$P\left(E\right)$.

Answer 1

Given, $P\left(\text{not}E\right)=0.95$

Thus $P\left(E\right)=1-P\left(\text{not}E\right)$

$\Rightarrow P\left(E\right)=1-0.95$

$\Rightarrow P\left(E\right)=0.05$