If $P S ⊥ Q R$ and $P Q = a, P R = b, Q S = c, P R = b$ and $R S = d,$ then prove that $(a + b) (a - b) = (c + d) (c - d)$

Open in App

Solution

REF.Image
$Q R = a^{2} - b^{2}$
also,
$Q R = c^{2} - d^{2}$
$∴ a^{2} - b^{2} = c^{2} - d^{2}$
$(a - b) (a + b) = (c - d) (c + d)$

Suggest Corrections

Similar questions

s e g P S ⊥ s i d e Q R

P Q = a, P R = b, Q S = c

R S = d

(a + c) (a - c) = (b + d) (b - d)

Δ P Q R

P D ⊥ Q R

Δ P Q R

P D ⊥ Q R

In the given figure, $R S = Q T$ and $Q S = R T .$ Then which of the following options is correct?

Δ P Q R

P D ⊥ Q R

D

Q R

P Q = a, P R = b, Q D = c

D R = d

(a + b) (a - b) = . . . . . . . . . .

Join BYJU'S Learning Program