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Question

If PS is the median of the triangle with vertices P(2, 2), Q(6, -1) and R(7, 3) then equation of the line passing through (1, -1) and parallel to PS is


A

4x7y11=0

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B

2x+9y+7=0

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C

4x+7y+3=0

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D

2x9y11=0

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Solution

The correct option is B

2x+9y+7=0


Coordinate of S=(7+62,312)=(132,1)
[ S is mid-point of the QR]


Slope of the line PS is 29.
Required equation passes through (1, -1) and parallel to PS is
y+1=29(x1)2x+9y+7=0


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