If PS is the median of the triangle with vertices P(2, 2), Q(6, -1) and R(7, 3) then equation of the line passing through (1, -1) and parallel to PS is
2x+9y+7=0
Coordinate of S=(7+62,3−12)=(132,1)
[∵ S is mid-point of the QR]
Slope of the line PS is −29.
Required equation passes through (1, -1) and parallel to PS is
y+1=−29(x−1)⇒2x+9y+7=0