Question

If PS is the median of the triangle with vertices P(2, 2), Q(6, -1) and R(7, 3) then equation of the line passing through (1, -1) and parallel to PS is

• A. $4x-7y-11=0$
• B. $2x+9y+7=0$
• C. $4x+7y+3=0$
• D. $2x-9y-11=0$

Answer 1

The correct option is B

$2x+9y+7=0$

Coordinate of $S=(\frac{7+6}{2},\frac{3-1}{2})=(\frac{13}{2},1)$
[$\because$ S is mid-point of the QR]


Slope of the line PS is $\frac{-2}{9}$.
Required equation passes through (1, -1) and parallel to PS is
$y+1=\frac{-2}{9}(x-1)\Rightarrow 2x+9y+7=0$