If PSP′ is a focal chord of the parabola y2=4ax and SL is its semi latusrectum then SP,SL,SP′ are in
A
AP
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B
HP
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C
GP
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D
AGP
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Solution
The correct option is C HP Let P=(at2,2at),∴P′=(at2,−2at) S=(a,0),L=(a,2a) SL=2a Now SP=√(a−at2)2+(2at)2=a+at2 SP′=√(a−at2)2+(−2at)2=a+at2=a+at2t2 Now clearly,