If PSQ is a focal chord of the conic where S is the focus lr- 1-e cos- then 1SP-1SQ-

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If PSQ is a...

Question

If $P S Q$ is a focal chord of the conic where $S$ is the focus $\frac{l}{r} = 1 - e cos θ$ then $\frac{1}{S P} + \frac{1}{S Q} =$

\frac{1}{l}

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\frac{2}{l}

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\frac{3}{l}

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\frac{4}{l}

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Solution

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Similar questions

P S P^{1}, Q S Q^{1}

\frac{l}{r} = 1 + cos θ

\frac{1}{S P . S P^{1}} + \frac{1}{S Q . S Q^{1}}

\frac{l}{r} = 1 + e cos θ, \frac{1}{S P} + \frac{1}{S Q} = \frac{2}{l}

P S Q

y^{2} = 8 x

S P = 6

l (S Q)

(

S

)

P S Q

y^{2} = 8 x

S P = 6

S Q

S

P S Q

\frac{x^{2}}{4} + \frac{y^{2}}{9} = 1

\frac{1}{S P} + \frac{1}{S Q} =

PSQ is a focal chord of the ellipse $\frac{x^{2}}{4} + \frac{y^{2}}{9}$ = 1 then $\frac{1}{S P} + \frac{1}{S Q}$ =

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