If PTC non taster population is 16 % then percent population of Heterozygous taster is
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Solution
We know that 16% of the pop. is recessive so we call that q2 There is in fact 2 formulas needed : p2 + q2 + 2pq = 1(population) and p+q=1 AA aa Aa
so √q2=√.16 --> q= .4 --> so p= .6 when you subtract .4 from 1 What heterogeneous means is the Aa or 2pq. Since we already have p and q we just multiply them and then multiply that answer by 2 2(.6 x .4)= .48 = 48% of the pop/ is heterogeneous