If pure "p" orbitals are involved in molecule formation, then the shape of $H_{3} O^{+}$ will be:

pyramidal

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tetrahedral

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angular

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planar

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Solution

The correct option is A pyramidal

$H_{3} O^{+}$ will have three bond pairs and one lone pair and shape same as $N H_{3}$ therefore is pyramidal.
The hydroxonium ion is isoelectronic with ammonia, and has an identical shape -pyramidal
Hence option A is correct.

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