If $p x^{3} + q x^{2} + r x + s = 0$ is a reciprocal equation of second type, then

p = s, q = r

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p = - s, q = - r

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p = s, q = - r

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p = - s, q = r

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Solution

The correct option is B $p = - s, q = - r$
If $p x^{3} + q x^{2} + r x + s$ is a R.E. of the second type then we know that
$a_{n} = - a_{n - r}$ where
$a_{n}$ are the coefficient of the equation $f (x) = 0$
So as $f (x) = p x^{3} + q x^{2} + r x + s$
$p = - s$ and $q = - r$

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