If $p (y) = 2 y^{3} - 6 y^{2} - 5 y + 7$ then find $p (2)$ .

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Solution

Given: $p (y) = 2 y^{3} - 6 y^{2} - 5 y + 7$
Put $y = 2$ , we get
$p (2) = 2 \times (2)^{3} - 6 \times (2)^{2} - 5 \times (2) + 7$
$= 2 \times 8 - (6 \times 4) - 10 + 7$
$= 16 - 24 - 10 + 7$
$= - 11$

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