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Question

If Q (0, 1) is equidistant from P (5, - 3) and R (x, 6), find the value of x.

A
x = 4
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B
x = -4
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C
x = 5
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D
x = -5
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Solution

The correct options are
A x = 4
B x = -4
PQ = QR
(50)2+(31)2=(0x)2+(16)2
(5)2+(4)2=(x)2+(5)2
25+16=x2+25
41=x2+25
16=x2
x=±4
Therefore, point R is (4, 6) or ( - 4, 6).

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