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Nuclear Fusion

If Q1 and ...

Question

If $Q_{1}$ and $Q_{2}$ are the energies released in the fusion of hydrogen in Carbon - nitrogen cycle and proton - proton cycle respectively, then

A

Q_{1}

>

Q_{2}

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B

Q_{1}

=

Q_{2}

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C

Q_{1}

<

Q_{2}

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D

Q_{1}

= 2

Q_{2}

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Solution

The correct option is B $Q_{1}$ = $Q_{2}$
In both proton - proton cycle and carbon - Nitrogen cycle the value of energy as calculated from mass defect comes out to be 26.7 MeV.
So, $Q_{1} = Q_{2}$

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