The correct option is C 546 K
From the first law of thermodynamics we know,
△U=q+w
As it is an isothermal process the temperature remains constant,
△U=0,
which means,
q=−w
so, work done for a reversible isothermal process =−10454 J
Also, work done,(w) for a reversible isothermal process is given by
wrev=−2.303×n×R×T logP1P2
Given
P1=initial pressure=1.0 bar
P2=final pressure=0.1 bar
So, putting the values we get;
−10454=−2.303×1×8.314×T× log10.1
Solving this, we get
T=546.18 K