Question

If $Q$ is the image of the point $P(2,3,4)$ under the reflection in the plane $x-2y+5z=6$. then equation of the line $PQ$ is

• A. $\frac{x-2}{-1}=\frac{y-3}{2}=\frac{z-4}{5}$
• B. $\frac{x-2}{1}=\frac{y-3}{-2}=\frac{z-4}{5}$
• C. $\frac{x-2}{-1}=\frac{y-3}{-2}=\frac{z-4}{5}$
• D. $\frac{x-2}{1}=\frac{y-3}{2}=\frac{z-4}{5}$

Answer 1

The correct option is B $\frac{x-2}{1}=\frac{y-3}{-2}=\frac{z-4}{5}$

Since, the point $Q$ is image of $P$, therefore $PQ$ is perpendicular to the plane $x-2y+5z=6$
$\therefore$ Required equation of the line is
$\frac{x-2}{1}=\frac{y-3}{-2}=\frac{z-4}{5}$