If fx- 1-tan x - 1- 2 sin x -for x- 4 is continous at x- 4 - find f- 4

Since If f(x)= 1 tan x #160; / 1 √( 2 )sin x #160; ,for x≠π #160; / 4 is continous at x=π #160; / 4 , So, limit of function must exi ...

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Continuity of a Function

If fx= 1-tan...

Question

$I f f (x) = \frac{1 - tan x}{1 - \sqrt{2} sin x}, f o r x \neq \frac{π}{4} i s c o n t i n o u s a t x = \frac{π}{4}, f i n d f (\frac{π}{4})$

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lim x \to π / 4 \frac{1 - tan x}{1 - \sqrt{2} sin x}

l i m x \to \frac{π}{4} \frac{1 - t a n x}{1 - \sqrt{2} s i n x}

lim x \to \frac{π}{4} \frac{1 - tan x}{1 - \sqrt{2} sin x}

f (x) = \frac{1 - t a n x}{1 - \sqrt{2} s i n x}

x \neq \frac{π}{4}

x = \frac{π}{4}

f (\frac{π}{4})

${lim}_{x \to \frac{π}{4}} \frac{1 - t a n x}{1 - \sqrt{2} s i n x}$

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