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Question

If x(3π2,2π), then the value of the expression sin1[cos{cos1(cosx)+sin1(sinx)}]

A
π2
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B
π2
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C
0
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D
π
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Solution

The correct option is B π2
sin1[cos{cos1(cosx)+sin1(sinx)}]sin1[cos{2πx+x2π}]=sin1[1]=π2

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