Question

If quadratic equation $k{x}^2+2x+k=0$ has two equal roots, then find the value of $k$

Answer 1

According to question,

$k{x}^2+2x+k=0$

As, roots are equal,

So, Discriminant, $D=0$

$⟹2^2-4k^2=0$

$⟹k^2=1$

Hence, $k{=}_{-}^{+}1$