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Question

If R1 and R2 are filament resistances of a 200 W and a 100 W bulb respectively, designed to operate on the same voltage, then:

A
R1=R2
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B
R2=2R1
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C
R2=4R1
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D
R1=4R2
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Solution

The correct option is C R2=2R1
Power, P=V2R
For first bulb power, P1=V21R1
For second bulb power
, P2=V22R2
Divide the above equations:
P1P2=V21×R2V22×R1
Substitute: P1=200W and P2=100W and V1=V2 (as bulbs operate at same voltage)

200100=R2R1

R2=2R1

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