If R1 and R2 are filament resistances of a 200 W and a 100 W bulb respectively, designed to operate on the same voltage, then:
A
R1=R2
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B
R2=2R1
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C
R2=4R1
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D
R1=4R2
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Solution
The correct option is CR2=2R1 Power, P=V2R For first bulb power, P1=V21R1 For second bulb power, P2=V22R2 Divide the above equations: P1P2=V21×R2V22×R1
Substitute: P1=200W and P2=100W and V1=V2 (as bulbs operate at same voltage)