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Question

If R1 and R2 are the filament resistances of a 200 W bulb and a 100 W bulb respectively designed to operate on the same voltage, then

A
R1=2R2
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B
R2=2R1
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C
R2=4R1
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D
R1=4R2
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Solution

The correct option is B R2=2R1
Given that,
Power of bulbs P1=200 WP2=100 W

The power P=VI, and I=V/R

On substituting we get, P=V2R.

Here, the power P1 used in case of R1 is P1=V2R1=200W..........(1)
The power P2 used in case of R2 is P2=V2R2=100W.........(2)
On taking ration,
P1P2=R2R1=200100.

Hence, R2=2R1.
Option B

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