Question

If $R=100\Omega ,L=10mH$ and $C={10}^{-4}F$. the value of resonant frequency will be nearly

• A. 50 cps
• B. 160 cps
• C. 100 cps
• D. 960 cps

Answer 1

The correct option is B 160 cps

At resonance $\omega =\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{10\times {10}^{-3}\times {10}^{-4}}}=1000rad/sec$
Frequency$=\frac{\omega }{2\pi }=160kHz$