If $r^{2} = l^{2} + d^{2}$ solve for $d$ , and find the value of ' $d$ ' if $r = 5$ and $l = 4$

Open in App

Solution

The given quadratic equation is $r^{2} = l^{2} + d^{2}$ .

Substitute $r = 5$ and $l = 4$ in the equation $r^{2} = l^{2} + d^{2}$ as follows:

$r^{2} = l^{2} + d^{2} \Rightarrow 5^{2} = 4^{2} + d^{2} \Rightarrow 25 = 16 + d^{2} \Rightarrow d^{2} = 25 - 16 \Rightarrow d^{2} = 9 \Rightarrow d = \sqrt{9} \Rightarrow d = \pm 3$

Hence, $d = \pm 3$ .

Suggest Corrections

Similar questions

(1) If A = 2πr², then solve for ‘r’ and find the value of ‘r’ when A = 77 and

(2) If V = πr²h, then solve for ‘r’ and find the value of ‘r’ when V = 176 and h = 14

(3) If r² = l² + d², then solve for ‘d’ and find the value of ‘d’ when r = 5 and l = 4.

(4) If c² = a² + b², then solve for ‘b’. If a = 8 and c = 17, find the value of ‘b’.

(5) If K = ½ mv², then solve for ‘v’ and find the value of ‘v’ when K = 100 and m = 2.

(6) If v² = u² + 2as, solve for ‘v’. If u = 0, a = 2 and s = 100, find the value of v.

a, b, c, d \in R,

a sec (200^{o}) - c tan (200^{o}) = d

b sec (200^{o}) + d tan (200^{o}) = c

(\frac{a^{2} + b^{2} + c^{2} + d^{2}}{b d - a c}) sin 20^{o}

l^{2} = r^{2} + h^{2}

a, b, c

d

a^{2} + b^{2} = 4

c^{2} + d^{2} = 1

a c + b d

sinθ = \frac{c}{\sqrt{c^{2} + d^{2}}}

Join BYJU'S Learning Program