If |r−6|=11 and |2q−12|=8 then the maximum value of ∣∣qr∣∣ is-
Find the value(s) of k so that PQ will be parallel to RS. Given :
(i) P (2, 4), Q (3, 6), R (8, 1) and S (10, k) (ii) P (5, -1), Q (6, 11), R (6, -4k) and S (7, k2)